Housekeeping Aide Job at Seneca Health Care Center LLC in Buffalo
Seneca Health Care Center LLC, Buffalo, NY, United States, 14266
Overview
Housekeeping Aide
Rate: $16.15-$18.61 / hour (depending on experience)
Location: Seneca Healthcare Facility
Shift: Full-time, Part-time
About Us
Join our caring team at Seneca Health Care Center, where we provide a clean, safe, and welcoming environment for residents and staff. We are seeking a Housekeeping Aide to support our housekeeping team in maintaining high standards of cleanliness and hygiene throughout the facility.
Job Description
As a Housekeeping Aide , you will be responsible for cleaning resident rooms, common areas, and facility spaces, ensuring they are maintained to the highest standards of cleanliness and safety. You will assist in providing a comfortable and pleasant environment for residents, staff, and visitors.
Responsibilities
- Clean and sanitize resident rooms, bathrooms, and common areas.
- Maintain cleanliness in dining areas, hallways, and facility offices.
- Ensure proper disposal of waste and linen.
- Assist with inventory management of cleaning supplies.
- Follow infection control and safety protocols.
- Report any maintenance or safety concerns promptly.
- Collaborate with the housekeeping team to meet cleanliness standards and maintain a safe environment.
Qualifications
- Previous experience in housekeeping or janitorial services preferred.
- Knowledge of cleaning procedures and safety standards in healthcare settings.
- Ability to work efficiently and independently.
- Strong attention to detail and time management skills.
- Good communication and teamwork skills.
Benefits
- Paid Time Off (PTO)
- Health, Vision, and Dental Insurance
- Life Insurance
- Referral Bonus Program
- Weekly or Same Day Pay Options
- Supportive Work Environment
Apply today to be part of a team committed to creating a clean and supportive environment for our residents and staff!